Here, the four fundamental operations — addition, subtraction, multiplication and division and also statements such as less than\ 'greater than, 'equal to', 'not equal to, etc. are represented by symbols, different from the usual ones. The questions involving these operations are set using artificial symbols. The candidate has to substitute the real signs and solve the questions accordingly, to get the answer.
Different types of questions covered in this chapter are as follows
- Symbol Substitution
- Balancing the Equation
- Interchange of Signs and Numbers
- Trick Based Mathematical Operations
Note:- While solving a mathematical expression, proceed according to the rule BODMAS —i.e., Brackets, Of, Division, Multiplication, Addition, Subtraction.
(36 -12) ÷4 + 6 + 2 x 3 = 24 ÷ 4 + 6 + 2 x 3 (Solving Bracket)
= 6 + 6 + 2 x 3 (Solving Division)
= 6+6+6 (Solving Multiplication)
= 18 (Solving Addition)
Type 1: Symbol Substitution
In this type of question, a candidate is provided with substitutes for various mathematical symbols, followed by a question involving the calculation of an expression or choosing the correct/ incorrect equation. The candidate is required to put in the real signs in the given equation and then solve the questions as required.
Ex 1: if ‘×’ means ‘-’, ‘÷’ means ‘+’, + means ‘×’, then 18 × 5 ÷ 5 +6 is equal to
Change of symbols according to the question,
? = 18 × 5 ÷ 5 +6 = 18 – 5 +5 × 6
= 18 – 5 + 30 = (18 +30) = 43
Type2: Balancing the Equation
In this type of questions, the signs in one of the alternatives are required to fill up the blank spaces for the signs to balance the given equation
Ex: If the following equations have to be balanced, then the signs of which of the following options will be used?
24 6 12 16 = 0
(a) - , + and +
(b) ÷, + and ÷
(c) -, - and -
(d) ÷, + and –
From Option (d)
Hence, option (d) is correct.
Type 3: Interchange of Signs and Numbers
In this type of questions, the given equation becomes correct and fully balanced when either two signs of the equation or both the numbers and the signs of the equation are interchanged. The candidate is required to find the correct pair of signs and numbers from the given alternatives.
Ex: Which one of the given interchanges in signs would make the given equation correct?
10 – 2 +9 ×2÷4=19
(a) – and ÷
(b) – and +
(c) ÷ and ×
(d) × and ÷
Let us check the options one by one
From option (a),
As options (a) gives us the correct answer. Hence, there is no need to check other options
Type 4: Trick Based Mathematical Operations
The questions are based on simple mathematical operations that do not come under any of the above-given types covered here. These questions can be based on several different patterns.
Ex: If 9 ×5×2 = 529 and 4 ×7×2 =724, then 3×9×8 =?
|Serial No.||Book Name||Author Name|
|1.||A Complete Resources for CTET: Mathematics and Pedagogy||Haneet Gandhi (Pearson)|
|2.||CTET & TETs for Class VI-VII Mathematics & Pedagogy||Arihant|
|3.||Quantitative Aptitude for Competitive Examinations||ABHIJIT GUHA and R.S. Aggarwal|
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