Question

# A car accelerates uniformly from 18 km/hr to 36 km/hr in 5s. Calculate the acceleration and the distance covered by the car at that time.

• 1.4 m/s2
• 2.3 m/s2
• 3.2 m/s2
• 4.1 m/s2
Option 4:1 m/s2
Solution

The acceleration of the car is 1 m/s2 and the distance traveled by car is 37.5 m at that time. Steps to Calculate the acceleration and the distance covered by the car at that time:

Step 1: It is given that

Initial velocity,

u = 18 km/hr = 5 m/s

Time, t = 5s

Final velocity,

v = 36 km/hr = 10 m/s

Step 2: We can use the formula

The first equation of motion is, v = u + at

The second equation of motion is, s = ut + ½ at2

Step 3: Determine the acceleration

Using the first equation of motion,

v = u + at

10 = 5 + a (5)

a = 1 m/s2

Step 4: Determine the distance covered

Using the second equation of motion, find the distance s.

s = ut + ½ at2

= 5 (5) + ½ (1) (5)2

= 37.5 m

### Acceleration

Acceleration can be defined as the rate of change of velocity with respect to time. It is a vector quantity because it has magnitude and direction. It can also be expressed as the second derivative of position.

### Types of Acceleration

1. Uniform Acceleration: When an object moves in a straight line with constant acceleration at equal time intervals, it is called uniform acceleration.

2. Non-Uniform Acceleration: Non-Uniform Acceleration occurs when an object moves with an increased speed at uneven time intervals.

3. Instantaneous Acceleration: The acceleration of an object at a specific point in time is called instantaneous acceleration.

Summary:

A car accelerates uniformly from 18 km/hr to 36 km/hr in 5s. Calculate the acceleration and the distance covered by the car at that time.

A car accelerates uniformly from 18 km/hr to 36 km/hr in 5s. The acceleration is 1 m/s2 and the distance covered is 37.5 m by the car in that time. Acceleration is the rate of velocity change based on time. write a comment
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