Question

# A ball hits a wall horizontally at 6 m/s. It rebounds horizontally at 4.4m/s. The ball is in contact with the wall for 0.04 s. What is the acceleration of the ball?

• 1.-260 m/s2
• 2.-250 m/s2
• 3.240 m/s2
• 4.260 m/s2
Option 1:-260 m/s2
Solution

The acceleration of the ball is -260 m/s². It is opposite to the initial facility which will help in retardation to slow the ball down. Steps to calculate the acceleration of the ball.

Now we have to assume that the ball is moving in a forward direction then,

● Initial velocity u = 6 m/s

● Time was taken during change of velocity = 0.04 s

● Final velocity v = 4.4 m/s = -4.4 m/s

We know that:

Acceleration = (v-u)/t = change in velocity/time

In simplification we get the:

a = ( -4.4 -6)/ 0.04

= -10.4/0.04

= -1040/4

In simplification we get the:

a = -260 m/s²

The acceleration of the ball is -260 m/s². Since it is moving against the original velocity, it will retard the ball and cause it to go more slowly.

If an object's velocity changes, it is said to have been accelerated. An object's velocity can alter depending on whether it moves faster or slower or in a different direction. A falling apple, the moon orbiting the Earth, and a car stopped at a stop sign are a few instances of acceleration.

Summary:

A ball hits a wall horizontally at 6 m/s. It rebounds horizontally at 4.4m/s. The ball is in contact with the wall for 0.04 s. What is the acceleration of the ball?

A ball hits a wall horizontally at 6 m/s. It rebounds horizontally at 4.4m/s. The ball is in contact with the wall for 0.04 s. The acceleration of the ball is -260 m/s². It is opposite to the initial facility which will help in retardation to slow the ball down. write a comment
Prev. Question
Next Question
Similar Questions
View All
Time, Speed and DistanceArithmetic Get solutions to similar questions at one place    GradeStack Learning Pvt. Ltd.Windsor IT Park, Tower - A, 2nd Floor, Sector 125, Noida, Uttar Pradesh 201303 help@byjusexamprep.com