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Question 1
Directions: In the following question two equations numbered I and II are given. You have to solve both the equations and answer the question.
I. x2 + 2x – 24 = 0
II. y2 – 6y – 27 = 0
II. y2 – 6y – 27 = 0
Question 2
Direction: In the following question, there are two equations. Solve the equations and answer accordingly.
I. x2 - 24x + 108 = 0
II. y =
II. y =
Question 3
Direction: In the question given below, two equations are provided. Solve the equations and establish the relationship between x and y.
I. 6x2 – 41x – 30 = 0
II. 5y2 – 40y – 45 = 0
II. 5y2 – 40y – 45 = 0
Question 4
Directions:Solve the following quadratic equations to find out the values of l and m. After that, find out the relationship between l & m and mark your answer accordingly.
I. 4m2 – 3m = 2m – 1
II. n2 + 12 = (√2)2 n
I. 4m2 – 3m = 2m – 1
II. n2 + 12 = (√2)2 n
Question 5
Directions: Solve the following quadratic equations to find out the values of l and m. After that, find out the relationship between l & m and mark your answer accordingly.
I. 2(m2 + 3) = 7m
II. n2 – 11n + 30 = 0
II. n2 – 11n + 30 = 0
Question 6
Direction: In the following question two equations are given in variables m and n. You have to solve these equations and determine the relation between m and n.
I. m2 – 9m + 20 = 0
II. n2 – 7n + 12 = 0
II. n2 – 7n + 12 = 0
Question 7
Direction: In the following question two equations are given in variables X and Y. You have to solve these equations and determine relation between X and Y.
I. x2 – 8x + 15 = 0
II. 2y2 – 19y + 45 = 0
II. 2y2 – 19y + 45 = 0
Question 8
Direction: In each question two equations numbered I and II are given you leave to solve both the equation are now answer.
I. x2 + 8x - 9 = 0
II. y2 - 5y + 4 = 0
I. x2 + 8x - 9 = 0
II. y2 - 5y + 4 = 0
Question 9
Directions: In the following questions two equations numbered I and II are given. You have to solve both equations.
I. x2 − 324 = 0
II. y = √324
I. x2 − 324 = 0
II. y = √324
Question 10
In the following questions, two equations I and II are given. You have to solve both the equation
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Jul 13PO, Clerk, SO, Insurance
