Solution
Given: f(x) = 4√3x2 + 5x - 2√3 = 0
To find the zeros of the quadratic equation, we can use the quadratic formula:
x = [-b ± √(b2 - 4ac)] / 2a
where a = 4√3, b = 5, and c = -2√3
Plugging in the values, we get:
x = [-5 ± √(52 - 4(4√3)(-2√3))] / 2(4√3)
Simplifying, we get:
x = [-5 ± √(25 + 96)] / (8√3)
x = [-5 ± √121] / (8√3)
x = (-5 ± 11) / (8√3)
So, the solutions are:
x = (-5 + 11) / (8√3) = 6 / (8√3) = √3/4
x = (-5 - 11) / (8√3) = -16 / (8√3) = -2/√3
Answer
The zeros of the quadratic polynomial f(x) are x = -2/√3 and x = √3/4.
Similar Questions:
- Find the zeros of the quadratic polynomial √3x² - 8x + 4√3.
- Find the Zeros of the Quadratic Polynomial 4u²+8u and Verify the Relationship between the Zeros and the Coefficient.
- For the Following, Find a Quadratic Polynomial whose Sum and Product Respectively of the Zeros are as Given. Also Find the Zeroes of the Polynomial by Factorization: 21/8, 5/16
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