Write the Complete Balanced Reaction (a) Potassium Bromide(Aq) + Barium Iodide(Aq) → Potassium Iodide(Aq) + Barium Bromide(S)

By K Balaji|Updated : November 9th, 2022

The balanced chemical reaction Potassium bromide(aq) + Barium iodide(aq) → Potassium iodide(aq) + Barium bromide(s) is 2KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s).

Balanced Chemical Equation

A chemical reaction that has the same amount of atoms of each element on the reactant and product sides is represented by a balanced chemical equation.

Word equation to symbolic equation:

  • In the described reaction, barium iodide and potassium bromide combine to generate barium iodide and potassium bromide.
  • You can visualise the chemical process as:

KBr (aq) + BaI2 (aq) → KI (aq) + BaBr2(s)

Potassium Bromide Barium iodide Potassium iodide Barium Bromide

ElementReactant SideProduct Side
K11
Br12
Ba11
I21

The table makes it obvious that the bromine and iodine atoms are out of equilibrium.

Step 2: Balancing the unbalanced atoms

  • We will set the KI coefficient to 2 to balance the iodine atoms.
  • Now the equation becomes

KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s)

ElementReactant SideProduct Side
K12
Br12
Ba11
I22

Now we will set the KBr coefficient to 2 in order to balance the remaining atoms.

The equation becomes,

2KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s)

ElementReactant SideProduct Side
K22
Br22
Ba1 1
I22

Hence, the balanced chemical equation is 2KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s)

Summary:-

Write the Complete Balanced Reaction (a) Potassium Bromide(Aq) + Barium Iodide(Aq) → Potassium Iodide(Aq) + Barium Bromide(S)

The balanced chemical reaction Potassium bromide(aq) + Barium iodide(aq) → Potassium iodide(aq) + Barium bromide(s) is 2KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s)

Related Questions:-

Comments

write a comment

CDS & Defence Exams

CDSCAPFAFCATTA ExamACC ExamOther ExamsPracticePreparation

Follow us for latest updates