Potassium Bromide + Barium Iodide gives Potassium Iodide + Barium Bromide
The question states "Write the Complete Balanced Reaction (a) Potassium Bromide(Aq) + Barium Iodide(Aq) → Potassium Iodide(Aq) + Barium Bromide(S)." A chemical reaction that has the same amount of atoms of each element on the reactant and product sides is represented by a balanced chemical equation. In the described reaction, barium iodide and potassium bromide combine to produce barium iodide and potassium bromide.
Step 1: Word equation to symbolic equation.
- In the described reaction, barium iodide and potassium bromide combine to generate barium iodide and potassium bromide.
- You can visualise the chemical process as:
KBr (aq) + BaI2 (aq) → KI (aq) + BaBr2(s)
Potassium Bromide + Barium Iodide gives Potassium Iodide + Barium Bromide
Element | Reactant Side | Product Side |
K | 1 | 1 |
Br | 1 | 2 |
Ba | 1 | 1 |
I | 2 | 1 |
The table makes it obvious that the bromine and iodine atoms are out of equilibrium.
Step 2: Balancing the unbalanced atoms.
- We will set the KI coefficient to 2 to balance the iodine atoms.
- Now the equation becomes
KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s)
Element | Reactant Side | Product Side |
K | 1 | 2 |
Br | 1 | 2 |
Ba | 1 | 1 |
I | 2 | 2 |
Step 3: Now we will set the KBr coefficient to 2 in order to balance the remaining atoms.
The equation becomes, 2KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s)
Element | Reactant Side | Product Side |
K | 2 | 2 |
Br | 2 | 2 |
Ba | 1 | 1 |
I | 2 | 2 |
Hence, the balanced chemical equation is 2KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s)
Summary:
Write the Complete Balanced Reaction (a) Potassium Bromide(Aq) + Barium Iodide(Aq) → Potassium Iodide(Aq) + Barium Bromide(S)
The balanced chemical reaction Potassium bromide(aq) + Barium iodide(aq) → Potassium iodide(aq) + Barium bromide(s) is 2KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s). The equation must be balanced so that each type of atom appears in equal amounts on both the left and right sides of the arrow. Changing the coefficients of the compound numbers put in front of compound formulas accomplishes this. The chemical identification of the compound would change if the subscripts were changed.
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