Write the Complete Balanced Reaction (a) Potassium Bromide(Aq) + Barium Iodide(Aq) → Potassium Iodide(Aq) + Barium Bromide(S)

By K Balaji|Updated : May 19th, 2023

The balanced chemical reaction Potassium bromide(aq) + Barium iodide(aq) → Potassium iodide(aq) + Barium bromide(s) is 2KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s). An equation for a chemical reaction is said to be balanced if both the reactants and the products have the same number of atoms and the total charge for each component of the reaction. In other words, both sides of the reaction have an equal balance of mass and charge.

In this post, we will discuss the frequently asked question "Write the Complete Balanced Reaction for Potassium Bromide + Barium Iodide → Potassium Iodide + Barium Bromide."

Potassium Bromide + Barium Iodide gives Potassium Iodide + Barium Bromide

The question states "Write the Complete Balanced Reaction (a) Potassium Bromide(Aq) + Barium Iodide(Aq) → Potassium Iodide(Aq) + Barium Bromide(S)." A chemical reaction that has the same amount of atoms of each element on the reactant and product sides is represented by a balanced chemical equation. In the described reaction, barium iodide and potassium bromide combine to produce barium iodide and potassium bromide.

Step 1: Word equation to symbolic equation.

  • In the described reaction, barium iodide and potassium bromide combine to generate barium iodide and potassium bromide.
  • You can visualise the chemical process as:

KBr (aq) + BaI2 (aq) → KI (aq) + BaBr2(s)

Potassium Bromide + Barium Iodide gives Potassium Iodide + Barium Bromide

ElementReactant SideProduct Side
K11
Br12
Ba11
I21

The table makes it obvious that the bromine and iodine atoms are out of equilibrium.

Step 2: Balancing the unbalanced atoms.

  • We will set the KI coefficient to 2 to balance the iodine atoms.
  • Now the equation becomes

KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s)

ElementReactant SideProduct Side
K12
Br12
Ba11
I22

Step 3: Now we will set the KBr coefficient to 2 in order to balance the remaining atoms.

The equation becomes, 2KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s)

ElementReactant SideProduct Side
K22
Br22
Ba11
I22

Hence, the balanced chemical equation is 2KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s)

Summary:

Write the Complete Balanced Reaction (a) Potassium Bromide(Aq) + Barium Iodide(Aq) → Potassium Iodide(Aq) + Barium Bromide(S)

The balanced chemical reaction Potassium bromide(aq) + Barium iodide(aq) → Potassium iodide(aq) + Barium bromide(s) is 2KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s). The equation must be balanced so that each type of atom appears in equal amounts on both the left and right sides of the arrow. Changing the coefficients of the compound numbers put in front of compound formulas accomplishes this. The chemical identification of the compound would change if the subscripts were changed.

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