# Write the Complete Balanced Reaction (a) Potassium Bromide(Aq) + Barium Iodide(Aq) → Potassium Iodide(Aq) + Barium Bromide(S)

By K Balaji|Updated : November 9th, 2022

The balanced chemical reaction Potassium bromide(aq) + Barium iodide(aq) → Potassium iodide(aq) + Barium bromide(s) is 2KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s).

### Balanced Chemical Equation

A chemical reaction that has the same amount of atoms of each element on the reactant and product sides is represented by a balanced chemical equation.

Word equation to symbolic equation:

• In the described reaction, barium iodide and potassium bromide combine to generate barium iodide and potassium bromide.
• You can visualise the chemical process as:

KBr (aq) + BaI2 (aq) → KI (aq) + BaBr2(s)

Potassium Bromide Barium iodide Potassium iodide Barium Bromide

 Element Reactant Side Product Side K 1 1 Br 1 2 Ba 1 1 I 2 1

The table makes it obvious that the bromine and iodine atoms are out of equilibrium.

Step 2: Balancing the unbalanced atoms

• We will set the KI coefficient to 2 to balance the iodine atoms.
• Now the equation becomes

KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s)

 Element Reactant Side Product Side K 1 2 Br 1 2 Ba 1 1 I 2 2

Now we will set the KBr coefficient to 2 in order to balance the remaining atoms.

The equation becomes,

2KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s)

 Element Reactant Side Product Side K 2 2 Br 2 2 Ba 1 1 I 2 2

Hence, the balanced chemical equation is 2KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s)

Summary:-

## Write the Complete Balanced Reaction (a) Potassium Bromide(Aq) + Barium Iodide(Aq) → Potassium Iodide(Aq) + Barium Bromide(S)

The balanced chemical reaction Potassium bromide(aq) + Barium iodide(aq) → Potassium iodide(aq) + Barium bromide(s) is 2KBr (aq) + BaI2 (aq) → 2KI (aq) + BaBr2(s)

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