When an object is placed at a distance of 50 cm from a concave spherical mirror, the magnification produced is -1/2 . Where should the object be placed to get a magnification of -1/5 ?
By BYJU'S Exam Prep
Updated on: September 13th, 2023
Given, a distance of an object from a concave spherical mirror, u = -50 cm
Magnification, m = -1/2
We have to find the image distance to get a magnification of -1/5
For a spherical mirror,
m = -v/u
-1/2 = -v/-50
v = -50/2
v = -25 cm
By using the mirror formula,
1/f = 1/v + 1/u
Where, f = focal length
v = image distance
u = object distance
So, 1/f = 1/-25 + 1/-50
1/f = -2-1 / 50
1/f = -3/50
f = -50/3 cm
From the question,
-1/5 = -v/u
v = u/5
So, -1/(50/3) = 1/(u/5) + 1/u
-3/50 = 5/u + 1/u
-3/50 = (5+1)/u
-3/50 = 6/u
-1/50 = 2/u
u = -2(50)
u = -100 cm
Therefore, the required image distance is 100 cm.
Summary:
When an object is placed at a distance of 50 cm from a concave spherical mirror, the magnification produced is -1/2. Where should the object be placed to get a magnification of -1/5?
When an object is placed at a distance of 50 cm from a concave spherical mirror, the magnification produced is -1/2. The object is placed at a distance of 100 cm to get a magnification of -1/5.
Related Questions:-