Tetrahedral Voids in FCC Structure
- Atoms can be found on the cube's faces.
- The atoms in the corner are divided across 8 cubes, with 18 contributions coming from each corner.
- The cube's corner has eight atoms in total.
- From each corner, total contribution = ⅛ x 8 = 1
- In a cube, contributions from the faces = 3
- Total atoms in an FCC structure = 4
- Atoms positioned at the four corners of a typical tetrahedron help create it.
- Due to the presence of atoms on the lattice, there are twice as many tetrahedral voids.
- A total number of tetrahedral voids = 2 x the number of atoms per unit cell.
- As shown below, the cubic tight packing of the atoms forms a tetrahedral layer.
- The layers are arranged alternately, with the second layer occupying the depression left by the first layer.
- A tetrahedral void is indicated by the "T".
- In comparison to the size of the actual molecules, the hole or vacuum is minuscule.
- Tetrahedral voids have a coordination number of 4, and there are twice as many voids as atoms in each unit cell.
- Four atoms make up each unit cell of the FCC lattice.
- Total tetrahedral voids = 2 x the number of atoms per unit cell.
- Total tetrahedral voids = 2 x 4 = 8.
- As a result, the FCC structure contains a total of 8 tetrahedral voids.
What is the total number of tetrahedral voids in FCC structure? 4, 8, 6, 12
There are a total of 8 tetrahedral voids in the FCC structure. FCC stands for face centered cubic wherein atoms are arranged center of each cube face of the cell and at the corners.