What is number of diagonals of Octagon?

By Raj Vimal|Updated : October 20th, 2022

(A) 14

(B) 18

(C) 20

(D) 12

The number of diagonals of Octagon is 20. In a polygon with n sides, the number of diagonals that may be formed by connecting their angular points is given by: nC2 - n = n x (n - 3)/2.

The polygon is an octagon, and it has n sides, which equals eight.

Diagonals of Octagon

We already know that the number of diagonals that can be drawn by connecting the angular points of a polygon with n sides can be calculated as follows:

nC2 - n = n x (n - 3)/2

⇒ No. of diagonals of Octagon = [8 (8 - 3)/2]

No. of diagonal of Octagon = 20.

Properties of Octagon

Typically, while discussing qualities, regular octagons come to mind.

  • Eight sides and eight angles make up these.
  • Both the sides and the angles have equal lengths.
  • A regular octagon has a total of 20 diagonals.
  • The internal angles' combined total is 1080°, where each angle is equal to 135°(135×8 = 1080)
  • sum of the octagon's outside angles is 360°, and each angle is 45°(45×8=360).

Summary:

What is number of diagonals of Octagon? (A) 14 (B) 18 (C) 20 (D) 12

The Octagon has 20 diagonals in total. By connecting the angular points of an n-sided polygon's angular points, the number of diagonals can be shown.

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