Two metallic oxides contain 27.6% and 30% oxygen respectively. If the formula of the first oxide is X3O4, the formula of the second will be: (a). XO (b). XO2 (c). X2O5 (d). X2O3

By Shivank Goel|Updated : August 12th, 2022

Given, that two metallic oxides contain 27.6% and 30% oxygen.

The formula of the first oxide is X₃O₄

We have to find the formula of the second oxide.

According to the question,

Oxygen content in the first oxide = 27.6%

The metallic content X in first oxide = 100 - 27.6 = 72.4%

Oxygen content in the second oxide = 30%

The metallic content X in second oxide = 100 - 30 = 70%

Using the chemical formula to find the number of moles,

72.4% of X = 3 moles of X

Now, 70% of X = 3/72.4 x 70

= 210/72.4

= 2.90 mol of X

≅ 2 mol of X

Similarly, 27.6% of O = 4 moles of O

Now, 30% of O = 4/27.6 x 30

= 120/27.6

= 4.34 mol of O

≅ 3

Now, X : O = 2 : 3

Therefore, the formula for the second oxide will be X₂O₃

Summary:

Two metallic oxides contain 27.6% and 30% oxygen respectively. If the formula of the first oxide is X3O4, the formula of the second will be: (a). XO (b). XO2 (c). X2O5 (d). X2O3

Two metallic oxides contain 27.6% and 30% oxygen respectively. If the formula of the first oxide is X₃O₄, the formula of the second will be X₂O₃.

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