The zeroes of the quadratic polynomial x² + 99x + 127 are

Let us use the quadratic formula

x = [-b ± √b² - 4ac]/ 2a

From the polynomial a = 1, b = 99 and c = 127

Substituting the values 

x = [-99 ± √99² - 4(1) (127)]/ 2(1)

x = [-99 ± √(9801 - 508)]/ 2

x = [-99 ± √9293]/2

x = [-99 ± 96.4]/2

Here

x = (-99 + 96.4)/ 2 = -2.6/2 = -1.3

x = (-99 - 96.4)/ 2 = -195.4/ 2 = -97.7

The roots are - 1.3 and -97.7.

So when you are asked, The zeroes of the quadratic polynomial x² + 99x + 127 are

1. both positive
2. both negative
3. one positive and one negative
4. both equal

Then the answer will be that the zeroes of the quadratic polynomial x² + 99x + 127 are both negative.

Summary:

The zeroes of the quadratic polynomial x² + 99x + 127 are

The zeroes of the quadratic polynomial x² + 99x + 127 are both negative.

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