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The Sum of Three Consecutive Multiples of 8 is 888. Find the Multiples.
By BYJU'S Exam Prep
Updated on: September 25th, 2023
To find the multiples of 8 whose sum is 888, we have to form an equation in the following way.
Let us take, first multiple = x, second multiple = x + 8, and third multiple = (x + 8) + 8
Given: first multiple + second multiple + third multiple = 888
Now we will solve the above equation,
first multiple + second multiple + third multiple = 888
x + x + 8 + (x + 8) + 8 = 888
x + x + 8 + x + 16 = 888
x + x + x + 8 + 16 = 888
3x + 24 = 888
3x = 888 – 24
3x = 864
x = 864 ÷ 3
x = 288
Therefore, the first multiple = x = 288,
second multiple = x + 8 = 288 + 8 = 296, and
third multiple = (x + 8) + 8 = 288 + 16 = 304.
Table of content
Three Consecutive Multiples of 8 whose Sum is 888
288, 296, and 304 are the three consecutive multiples of 8 whose sum is 888. The easy way to find the consecutive multiples of any number is to form a linear equation. Let us understand what a linear equation is.
An equation is said to be linear if the highest power of the variable is consistently 1. Another name for it is a one-degree equation. A linear equation with one variable has the standard form Ax + B = 0 where B is constant, A is a coefficient, and x is a variable.
Summary:
The Sum of Three Consecutive Multiples of 8 is 888. Find the Multiples.
The three consecutive multiples of 8 whose sum is 888 are 288, 296, and 304. These multiples can be easily obtained by forming a linear equation such as assume value 1st multiple ‘x’, 2nd multiple ‘x + 8’ and 3rd multiple (x + 8) + 8.
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