The energy difference between the states showing the transition should be at its smallest for the longest wavelength in the Balmer series (i.e., the first line), i.e. n2 = 3
1/λ = RH [1/22 - 1/32] = 5/36RH
Substituting the values we get:
λ = 36/5 x 1/RH = 36/ (5 x 109678) = 6.565 x 10-5 cm
In simplification we get the:
= 6565 Å
- A key piece of evidence for the quantized electronic structure of an atom is the hydrogen spectrum. As soon as an electric discharge passes through a gaseous hydrogen molecule, the molecule's hydrogen atoms disintegrate.
- The energetically excited hydrogen atoms cause the emission of electromagnetic radiation, which is what happens.
- The hydrogen emission spectrum includes distinct frequency radiation. These radiation series bear the names of the researchers who first identified them.
The shortest and the longest wavelength in the Balmer series of the hydrogen spectrum are? Rydberg constant, RH = 109678 cm-1
The shortest and the longest wavelength in the Balmer series of the hydrogen spectrum are 3647 Å and 6565 Å. Balmer proposed the equation for relating the wave number of the emitted spectral lines and the involved energy shells in 1885, based on experimental observations.