To solve this problem, let's assume the cost of one saree is ‘a’ and the cost of one shirt is ‘b’.
According to the given information, the price of 2 sarees and 4 shirts is Rs. 1600, which can be expressed as:
2a + 4b = 1600 ----(1)
It is also mentioned that with the same amount of money, one can buy 1 saree and 6 shirts, so we have:
a + 6b = 1600 ----(2)
In order to find the cost of 12 shirts, we need to multiply equation (2) by 2 to match the number of sarees:
2a + 12b = 3200 ----(3)
Now, let's subtract equation (1) from equation (3) to eliminate ‘a’:
(2a + 12b) - (2a + 4b) = 3200 - 1600
This simplifies to:
8b = 1600
b = 1600/8
b = 200
Now, substitute the value of ‘b’ into equation (2) to find the cost of one saree:
a + 6(200) = 1600
a + 1200 = 1600
a = 400
So, the cost of one saree is Rs. 400 and the cost of one shirt is Rs. 200.
To find the cost of 12 shirts, multiply the cost of one shirt by 12:
12 x 200 = Rs. 2400
Therefore, to buy 12 shirts, one would have to pay Rs. 2400.
The price of 2 sarees and 4 shirts is Rs. 1600. With the same money one can buy 1 saree and 6 shirts. If one wants to buy 12 shirts, how much shall he have to pay?
If the price of 2 sarees and 4 shirts is Rs. 1600. With the same money one can buy 1 saree and 6 shirts. If one wants to buy 12 shirts, he will have to pay Rs. 2400. Besides the equation method, you can solve it using the concept of ratios and proportions.
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