The number of Fe Atoms in 100g Haemoglobin if it contains 0.33% Fe. (Atomic Mass Of Fe=56) is?

By BYJU'S Exam Prep

Updated on: September 25th, 2023

The number of Fe Atoms in 100g Haemoglobin if it contains 0.33% Fe. (Atomic Mass Of Fe=56) is 3.54 x 1021. Steps to find the number of Fe Atoms in 100g Haemoglobin:

Step 1: It is given that,

WHb = 100

Amount (Fe) = 0.33%

Step 2: How to determine the mass of Fe atoms in 100g of Hb:

WFe = 0.33/100 x 100 = 0.33g

Step 3: Counting the moles of 0.33g of iron:

Weight of Fe / Atomic Mass of Fe equals the number of moles of iron.

nFe = WFe/ MFe = 0.33/56 = 5.89 x 10-3

Step 4: Now we have to calculate the number of Fe atoms in 100g Hb:

nFe = WFe/ MFe = number of atoms of Fe/ 6.022 x 1023 = 5.89 x 10-3

number of atoms of Fe/ 6.022 x 1023 = 5.89 x 10-3
Number of atoms of Fe = 5.89 x 10-3 x 6.022 x 1023
Number of atoms of Fe = 3.54 x 1021

Hence, the number of atoms in 100g Hb is 3.54 x 1021.

Table of content

1. The number of Fe Atoms in 100g Haemoglobin if it contains 0.33% Fe. (Atomic Mass Of Fe=56) is?

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