# The Least Count of a Stop Watch is 0.2 S. The Time of 20 Oscillations of a Pendulum is Measured to Be 25s. The Percentage Error in the Measurement of Time Will Be: (Correct Answer + 1, Wrong Answer - 0.25)

By K Balaji|Updated : November 9th, 2022

(a) 16%

(b) 1.8%

(c) 0.8%

(d) 0.1%

The percentage error in the measurement of time will be 0.8%

Given that

Least count of stopwatch = 20s

20 oscillation time period = 25.0 ± 0.2s

Percentage error in the measurement = 0.2/25.0 x 100 = 0.8%

### Percentage Error

The percent error is the distinction between the estimated value and the actual value in relation to the actual value. In other words, the relative error is multiplied by 100 to calculate the percent error.

How to calculate percentage error?

The steps for obtaining the % error are detailed below.

Step 1: Find the difference between two values. The order doesn't matter if we aren't paying attention to the sign. However, if we want to maintain the negative signs, we must deduct the original value from the calculated value. This is the value "error."

Step 2: Divide the error by the correct or ideal value using a division operation (not estimated or measured value). Consequently, we get a decimal number.

Step 3: To convert a decimal number into a percentage, multiply it by 100.

Step 4: To express the percent error value, add the percentage symbol (%).

Summary:-

## The Least Count of a Stop Watch is 0.2 S. The Time of 20 Oscillations of a Pendulum is Measured to Be 25s. The Percentage Error in the Measurement of Time Will Be: (Correct Answer + 1, Wrong Answer - 0.25) (a) 16% (b) 1.8% (c) 0.8% (d) 0.1%

The least count of a stop watch is 0.2 s. The time of 20 oscillations of a pendulum is measured to be 25s. The percentage error in the measurement of time will be 0.8%

Related Questions:-