We know that the activity of a radioactive substance is written as
A = Ao (1/2)TH/t/2
Where TH is the fraction of the original activity
t/2 is the half-life of a radioactive nuclide
Substituting the values
A/Ao = (1/2)150/100
By further simplification
A/Ao = (1/2)3/2
So we get
A/Ao = 1/2√2
Therefore, the fraction of original activity that will remain after 150 hours would be 1/2√2.
Summary:
The half-life of a radioactive nuclide is 100 hours. The fraction of original activity that will remain after 150 hours would be
2/3√2
1/2
1/2√2
⅔
The half-life of a radioactive nuclide is 100 hours. The fraction of original activity that will remain after 150 hours would be 1/2√2.
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