The Given Circuit Work as

Answer: B. Lowpass filter

The given circuit work as a low pass filter.

Solution:

We know that X_c=1/2πfC

At f=0

X_c=1/0=∞

Hence the capacitor acts as an open circuit.

V_out=V_in

At f=∞

X_c=1/∞=0

Hence the capacitor acts as a short circuit.

V_out=0

Generally the capacitance value in micro-farads hence at mid frequencies also the output cannot follow the input.

The given circuit work as a low pass filter.

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