The brown ring complex compound is formulated as [Fe (H2O)5NO] SO4. The oxidation state of Iron is? (a) +1 (b) +2 (c) +3 (d) +6

By Ritesh|Updated : November 10th, 2022

The oxidation state of Iron is +1. To determine whether nitrate ions are present in any solution, a chemical test known as a nitrate test is performed, during which the solution forms a brown ring in the test tube. The substance used in the aforementioned test, commonly known as the brown ring test, is prepared as [Fe (H2O)5NO] SO4. The Iron’s oxidation state in the complex [Fe (H2O)5NO] SO4, can be found as:

Consider the Iron metal is in the oxidation state x. The sulfate ion's oxidation state in this instance is -2, water's oxidation state is 0 and Nitroso NO's oxidation state is +1.

As a result, the iron's oxidation state can be determined as follows:

X + (+1) + 5 (0) = +2

X = +1

Brown Ring Test Procedure

The brown ring test is another name for a typical nitrate test. This is how the experiment can be carried out:

Step 1: Take the solution of nitrate.

Step 2: Add iron(II) sulfate

Step 3: Slowly add concentrated sulphuric acid (H2SO4) such that the acid added forms a layer below the aqueous solution.

Summary:

The brown ring complex compound is formulated as [Fe (H2O)5NO] SO4. The oxidation state of Iron is? (a) +1 (b) +2 (c) +3 (d) +6

The brown ring complex compound is formulated as [Fe (H2O)5NO] SO4. The oxidation state of Iron is +1. The intersection of the two layers will result in the formation of a brown ring. This suggests that nitrate ions are present.

Comments

write a comment

CDS & Defence Exams

CDSCAPFAFCATTA ExamACC ExamOther ExamsPracticePreparation

Follow us for latest updates