- Home/
- CDS & Defence/
- Article
The brown ring complex compound is formulated as [Fe (H2O)5NO] SO4. The oxidation state of Iron is? (a) +1 (b) +2 (c) +3 (d) +6
By BYJU'S Exam Prep
Updated on: September 25th, 2023
The oxidation state of Iron is +1. To determine whether nitrate ions are present in any solution, a chemical test known as a nitrate test is performed, during which the solution forms a brown ring in the test tube. The substance used in the aforementioned test, commonly known as the brown ring test, is prepared as [Fe (H2O)5NO] SO4. The Iron’s oxidation state in the complex [Fe (H2O)5NO] SO4, can be found as:
Consider the Iron metal is in the oxidation state x. The sulfate ion’s oxidation state in this instance is -2, water’s oxidation state is 0 and Nitroso NO’s oxidation state is +1.
As a result, the iron’s oxidation state can be determined as follows:
X + (+1) + 5 (0) = +2
X = +1
Table of content
Brown Ring Test Procedure
The brown ring test is another name for a typical nitrate test. This is how the experiment can be carried out:
Step 1: Take the solution of nitrate.
Step 2: Add iron(II) sulfate
Step 3: Slowly add concentrated sulphuric acid (H2SO4) such that the acid added forms a layer below the aqueous solution.
Summary:
The brown ring complex compound is formulated as [Fe (H2O)5NO] SO4. The oxidation state of Iron is? (a) +1 (b) +2 (c) +3 (d) +6
The brown ring complex compound is formulated as [Fe (H2O)5NO] SO4. The oxidation state of Iron is +1. The intersection of the two layers will result in the formation of a brown ring. This suggests that nitrate ions are present.