The Brakes Applied by a Car Produces an Acceleration of 6 M/s2 in Opposite Direction of Motion. If the Car Takes 2 Sec to Stop After the Application of Brakes. Calculate Distance During This Time

By BYJU'S Exam Prep

Updated on: September 25th, 2023

The brakes applied by a car produces an acceleration of 6 m/s² in opposite direction of motion. If the car takes 2 sec to stop after the application of brakes. The distance travelled during this time is 12 m.

Step 1 – It is given that

Time t = 2s

Acceleration a = 6 m/s²

Final velocity v = 0 m/s

Consider u as the initial velocity

Step 2 – Calculate the distance

We know that the third equation of motion,

v² – u² = 2as

Substituting the values we get

0² – u² = 2 (-6) s

On simplifying we get

12s = u² …. (1)

Assume the distance as s

Using the first equation of the motion we can write as

v = u + at

0 = u + (-6) 2

On simplifying we get

u = 12 m/s

Substituting u in equation (1)

We get

12s = 12²

s = 12 m

Therefore, the distance travelled is 12 m

Table of content

1. The Brakes Applied by a Car Produces an Acceleration of 6 M/s2 in Opposite Direction of Motion. If the Car Takes 2 Sec to Stop After the Application of Brakes. Calculate Distance During This Time

Equations of Motion Applications

We can now employ the three equations of motion to solve kinematic issues as a result of having seen them all. Simply identifying all of the parameters will allow us to select the proper equation and solve for the necessary parameter.
Calculating optical characteristics also makes use of the equations of motion.

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