# The Brakes Applied by a Car Produces an Acceleration of 6 M/s2 in Opposite Direction of Motion. If the Car Takes 2 Sec to Stop After the Application of Brakes. Calculate Distance During This Time

By K Balaji|Updated : November 7th, 2022

The brakes applied by a car produces an acceleration of 6 m/s2 in opposite direction of motion. If the car takes 2 sec to stop after the application of brakes. The distance travelled during this time is 12 m.

Step 1 - It is given that

Time t = 2s

Acceleration a = 6 m/s2

Final velocity v = 0 m/s

Consider u as the initial velocity

Step 2 - Calculate the distance

We know that the third equation of motion,

v2 - u2 = 2as

Substituting the values we get

02 - u2 = 2 (-6) s

On simplifying we get

12s = u2 …. (1)

Assume the distance as s

Using the first equation of the motion we can write as

v = u + at

0 = u + (-6) 2

On simplifying we get

u = 12 m/s

Substituting u in equation (1)

We get

12s = 122

s = 12 m

Therefore, the distance travelled is 12 m

### Equations of Motion Applications

• We can now employ the three equations of motion to solve kinematic issues as a result of having seen them all. Simply identifying all of the parameters will allow us to select the proper equation and solve for the necessary parameter.
• Calculating optical characteristics also makes use of the equations of motion.

Summary:-

## The Brakes Applied by a Car Produces an Acceleration of 6 M/s2 in Opposite Direction of Motion. If the Car Takes 2 Sec to Stop After the Application of Brakes. Calculate Distance During This Time

A car's brakes cause a 6 m/s2 acceleration in the opposing direction of motion. if the car stops after applying the brakes after 2 seconds. This time period covered a distance of 12 m. The equation of motion can be used to calculate the optical characteristics

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