By : Neha Uppal
Updated : Nov 19, 2020, 17:11
Arithmetical reasoning and figural classification questions are asked in almost every SSC and Railway related competitive exams - be it SSC CGL, SSC CHSL, SSC JE, HSSC Patwari, HSSC Canal Patwari, HSSC Sachiv, HSSC Clerk, Delhi Police, RRB Group D, RRB JE, RRB NTPC, RRB ALP, SSC MTS, SSC CPO, SSC Steno, SSC Constable or any other related competition in government sector in India.
Arithmetical reasoning consists of a numeral or a word problem to be solved using basic arithmetic. These questions encircle a variety of concepts to solve using basic mathematics like ages and weights, number system, ratio and proportion, profit, loss and discounts, time and distance, sequences and patterns, fractions and percentages, time and work, simple and compound interest, HCF and LCM, pipes and cisterns, games and tournaments, probability, square roots etc.
Figural classification questions are the means to judge a candidate’s non-verbal capabilities, keen observance and general intelligence quotient. In such types of questions, mainly a group of figures except one belongs to a particular pattern, whereas the ignored one is the odd one out not resembling that pattern and the candidate has to identify this odd patterned option. As an example, to one such figural classification question
Counting numbers 1, 2, 3, 4, 5, ... are called natural numbers
All counting numbers together with zero form the set of whole numbers. Thus, (i) 0 is the only whole number which is not a natural number. (ii) Every natural number is a whole number.
A number divisible by 2 is called an even number, e.g., 2, 4, 6, 8, 10, etc.
A number not divisible by 2 is called an odd number. e.g., 1, 3, 5, 7, 9, 11, etc
A number greater than 1 is called a prime number, if it has exactly two factors, namely 1 and the number itself.
Numbers greater than 1 which are not prime, are known as
composite numbers, e.g., 4, 6, 8, 9, 10, 12.
Two numbers a and b are said to be co-primes, if their H.C.F. is 1. e.g., (2, 3), (4, 5), (7, 9), (8, 11), etc. are co-primes
(i) a * (b + c) = a * b + a * c, and (ii) a * (b-c) = a * b - a * c
If we divide a given number by another number, then:
Dividend = (Divisor x Quotient) + Remainder
Basic and important formulae
If every upcoming term of a progression differs from its previous term by a constant value, then it is called an AP.
A GP is where every term holds a constant ratio with its previous term
Highest Common Factor
The H.C.F. of two or more than two numbers is the greatest number that divides each of them exactly
Least Common Multiple
The least number which is exactly divisible by each one of the given numbers is called their L.C.M.
Laws of Indices, and Law of Surds
The ratio of two quantities a and b in the same units is the fraction a/b and we write it as a:b
The equality of two ratios is called proportion.
If a: b = c: d, we write, a: b:: c : d and we say that a, b, c, d are in proportion
Two quantities are said to be directly proportional if on the increase (or decrease) of the one, the other increases (or decreases) to the same
Two quantities are said to be inversely proportional if on the increase of the one, the other decreases to the same extent and vice-versa.
Time and distance
Speed=distance/time, Time=distance/speed, and distance=time*speed.
Verbal & Non-Verbal Reasoning
R. S. Aggarwal
Verbal & Non-Verbal Reasoning (Hindi)
Fast Track Objective (arithmetic reasoning)
For Notes, Study Material and Online Quiz (thousands of questions to practice are available)
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1- How to solve the arithmetic problems related to ages? Provide an example.
Problems on age could also be solved by formulating the subjective question into mathematical equations. As an example, let us solve a related problem:
Rajeev's age after 15 years will be 5 times his age 5 years back. What is the present age of Rajeev?
The present problem could be solved as: Let Rajeev's present age be x years. Then,
Rajeev's age after 15 years = (x + 15) years.
Rajeev's age 5 years back = (x - 5) years.
Therefore, x + 15 = 5 (x - 5), or x + 15 = 5x – 25, or 4x = 40, or x = 10.
Hence, Rajeev's present age = 10 years.
2- Provide the solution for this figural problem?
As all other figures can be rotated into each other, the only odd one out is an option (c).
3- Find the remainder when 231 is divided by 5?
As 210 = 1024. Unit digit of 210 x 210 x 210 is 4 [as 4 x 4 x 4 gives unit digit 4].
Therefore, Unit digit of number 231 is 8. Now, 8 when divided by 5, gives 3 as remainder. Hence, 231 when divided by 5, gives 3 as remainder.
4- What will be the product of all the numbers on a telephone?
One of the numbers on the telephone will be zero which gives us the product of all the numbers as zero.
5- What could be the proportionate image at “?” ?
Answer will be (C), as following the symmetry the image at (C) will be proportional.