Solve the Following Quadratic Equation by Factorization 3×2-2√6x+2=0
By BYJU'S Exam Prep
Updated on: October 17th, 2023
Solve the following quadratic equation by factorization 3x2-2√6x+2=0
Given equation: 3x2-2√6x + 2 = 0
To solve this equation by factorization, we can follow these steps:
- Step 1: Identify the coefficients of the equation: a = 3, b = -2√6, and c = 2
- Step 2: Factor out any common factor among the terms, if possible.
- Step 3: Rewrite the middle term (bx) by splitting it into two terms such that their coefficients multiply to give ac, the product of the coefficients of the quadratic equation.
- Step 4: Rewrite the middle term using the numbers found in Step 3.
- Step 5: Group the terms in pairs and factor out the common factors.
- Step 6: Factor out the common binomial factor.
- Step 7: Set each factor equal to zero and solve for the desired answer.
Table of content
Solve the Following Quadratic Equation by Factorization 3x2-2√6x+2=0
Solution:
Rewrite the equation:
3x^2 – 2√6x + 2 = 0
3x^2 – √6x – √6x + 2 = 0
Finding out the common term:
√3x(√3x-√2) – √2 (√3x-√2) = 0
(√3x – √2)^2 = 0
On solving for for x, we will get
x = ±√(2/3)
So the correct solutios are: x = √(2/3) and x = -√(2/3)
Answer:
On Solving the Following Quadratic Equation by Factorization 3x2-2√6x+2=0, we get x = √(2/3) and x = -√(2/3)
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