There is 900 mA of current through a wire with 40 turns. What is the reluctance of the magnetic circuit if the flux is 400 Wb?

Answer: Option D. 90,000 At/Wb

There is 900 mA of current through a wire with 40 turns. 90,000 At/Wb is the reluctance of the magnetic circuit if the flux is 400 Wb. 

Solution

Given,

Number of turns N=40,

Current through wire I=900 mA,

Flux, ϕ=400 μWb,

We know that,

Flux, ϕ =M.M.F/ Reluctance=N.I/R 

So, the reluctance of the magnetic circuit is, 

R=N.I/ ϕ

R=40×900×10^-3/400×10^-6

R=90,000 At/Wb

Hence, 90,000 At/Wb is the reluctance of the magnetic circuit if the flux is 400 Wb. 

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