# Radiation Heat Transfer Study Notes for Mechanical Engineering

By Akhil Gupta|Updated : September 17th, 2021

(i) Thermal energy emitted by matter as a result of vibrational and rotational movements of molecules, atoms and electrons.

(ii) The energy is transported by electromagnetic waves (or photons).

(iii) Radiation requires no medium for its propagation, therefore, can take place also in vacuum.

(i) Thermal energy emitted by matter as a result of vibrational and rotational movements of molecules, atoms and electrons.

(ii) The energy is transported by electromagnetic waves (or photons).

(iii) Radiation requires no medium for its propagation, therefore, can take place also in vacuum.

BASIC DEFINITIONS:

TOTAL HEMISPHERICAL EMISSIVE POWER (E)

(i) It is defined as the radiation energy emitted from the surface of a body per unit time & per unit area in all possible hemispherical directions integrated over all the wavelengths (in J/s m2 or W/m2).

BLACK BODY

(i) Different bodies emits different amount of radiation even if they are at same temperature.

(ii) A body which emits maximum amount of radiation at a given temperature is known as BLACK BODY.

(iii) A black body is defined as perfect emitter and absorber of radiation.

TOTAL EMISSIVITY (Є)

Total emissivity of a body is defined as the ratio between total hemispherical emissive power of a non-black body & total hemispherical emissive power of a black body both being at the same temperature.

MONOCHROMATIC (OR) SPECTRAL EMISSIVE POWER (Eλ):

Eλ at a particular wavelength λ is defined as a quantity which when multiplied by dλ shall give the radiation energy emitted from the surface of a body per unit time per unit area in the wavelength region λ to λ + dλ.

ABSORPTIVITY (α), REFLECTIVITY (ρ) & TRANSMISSIVITY (τ)

• Absorptivity(α) is the fraction of incident radiation absorbed.
• Reflectivity(ρ) is the fraction of incident radiation reflected.
• Transmissivity (τ) is the fraction of incident radiation transmitted.

ABSORPTIVITY (α) = 50/100 = 0.5 = Fraction of radiation energy incident upon a surface which is absorbed by it.

REFLECTIVITY (ρ) = 25/100 = 0.25 = Fraction of radiation energy incident upon a surface which is reflected by it.

TRNASMISSIVITY (τ) = 25/100 = 0.25 = Fraction of radiation energy incident upon a surface which is transmitted by it.

• FOR ANY BODY

α + ρ + τ = 1

• For opaque body, which do not transmit any energy,

τ = 0,  α + ρ = 1

• For black body, α = 1 [as it absorbs all energy incident]
• For white body, which reflects all energy incident ,τ  = 1

The law states that whenever a body is in thermal equilibrium with its surrounding’s its emissivity is equal to its absorptivity.

α = ϵ

STEFAN BOLTZMANN’S Law:

The law states that the total hemispherical emissive power of a black body is directly proportional to fourth power of the absolute temperature of black body.

Stefan BoltzmannConstant= 5.67 × 10-8 W/m2 k4

The planck law describes the theoretical spectral distribution for the emissive power of a black body which is the amount of radiation energy emitted by a blackbody at a thermodynamic temperature T per unit time per unit surface area and per unit wavelength.

WEIN’S DISPLACEMENT LAW:

The wavelength at which Ewill be maximum at a specified temperature can be found out by differentiating E w.r.t  λ and then putting equal to zero.

We get,  λmT = 2897.8  μmK

LAMBERT’S COSINE LAW

The intensity of radiation in a direction θ from the normal to a diffuse emitter is proportional to cosine of the angle θ.

I= In cos θ, I= normal intensity of radiation

The ideal intensity Ib is defined as the energy emitted from an ideal body(black body which is diffuse emitter) ,per unit projected area, per unit time ,per unit solid angle.

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write a comment

Amityush RoyNov 5, 2017

Ankit KumarMay 19, 2018

The work function of metal is 3.8 EV and 2200 Angstrom wavelength light falls on its face out kinetic energy of emitted photon from this surface. Given plank constant h= 6.6*10^-34 joule/ sec
does the emission from body is depend on material property ??

Abhishek GautamAug 3, 2018

Thank you Sir @Vineet Vijay

Manoj DasAug 3, 2018

Thanks

Rituraj kumarAug 3, 2018

Yes..thats why some bodies are blackbody .

Chirag ShahAug 30, 2019

For study materials related to ypur engineering field just msg on chiragbest420@gmail.com

vsang r6Aug 30, 2019