In this article, we will learn important theorems and concepts of the circle. You just need to practice questions based on these theorems and concepts.
Let the radius of circle is ‘R’, diameter = D
(1) Maximum area of triangle = R2
If the given triangle is right angle triangle and its base is the diameter of the circle. Then, the maximum possible area of the triangle will be R2.
(2) If AB and CD are two chords intersecting each other at P.
(3) If PA and PB are two tangents and LM is the tangent intersecting both tangents PA and PB as given in the figure.
Then, PA = PB = 1/2 Perimeter of triangle PLM.
(4) If BA is a chord intersecting tangent T at P as in the below figure.
Then, PA x PB = PT2
5. This property is an important property of circle. It will help you to save your time in the exam. But don’t confuse between figure 5(a) and 5(b).
If angle AOC is x0 and BOD is y0, then angle APC and BPD will be equal to half of the sum of both angle x0 and y0.
Fig. 5 (a)
If angle AOC is x0 and BOD is y0, then angle APC and BPD will be equal to half of difference of the angle x0 and y0.
Fig. 5 (b)
(6) Quadrilateral formed by angle bisectors of a cyclic quadrilateral will be always a cyclic quadrilateral.
If given quadrilateral ABCD is a cyclic quadrilateral and RA, RB, PC and PD are angle bisectors of angle A, B, C and D. Then, quadrilateral PQRS formed by these angle bisectors will also be a cyclic quadrilateral.
Properties of Cyclic Quadrilateral:
1. The sum of diagonally opposite angle will always be equal to 1800.
PQRS is also a cyclic quadrilateral.
(7) In the given diagram, ABCD is a cyclic quadrilateral.
If AB is parallel to CD, and AD is parallel to BC then, diagonals AC and BD will also equal.
(8) Tangents
(a) If there are two circles which are at a distance apart from each other, then the maximum possible number of common tangents are 4.
Fig. 8 (a)
(b) If there are two circles touching each other externally, then the maximum number of possible common tangents are 3.
Fig. 8 (b)
(c) If there are two circles intersecting each other, then the maximum number of possible common tangents are 2.
Fig. 8 (c)
(d) If there are two circles touching each other internally, then the maximum number of possible common tangents are 1.
Fig. 8 (d) No. of common tangents = 1
(e) If there are two circles, either concentric or one is inside the another and do not touch.
then, the number of common tangents will be zero.
Fig. 8 (e) No. of common tangents = 0
(9)
(a) If PA and PB are two tangents from P on the circle at A and B.
then, PA = PB
(b) The line joining the centre and the point on the circle at which tangent meets will always be perpendicular to the tangent.
(10) If the tangent PAQ and chord AB makes an angle θ, then the angle made by chord AB on the circle will always be θ.
Similarly, If the tangent PAQ and chord AC makes an angle ϕ, then the angle made by chord AC on the circle will always be ϕ.
(10) If AB, BC, CD and AD are tangents on circle as given in the diagram,
Then AB + CD = BC + AD
(11) The distance between centres of two circles.
(a)
distance b/w centres = r1 - r2
(b)
distance b/w centres = r1 + r2
(12) Length of Direct Common Tangent.
If ‘d’ is the distance between centres of two circles and r1 and r2 are the radius of given two circles.
or
Fig. 12 (a) Fig. 12 (b)
Transversal common tangent
Note: Do not confuse between transversal and direct common tangent.
(12). This question is asked many times in SSC Exams. Remember the diagram as it is given, all three circles have a direct common tangent.
(13)
If PQ is diameter and PR||QS
Then, PQ = RS and
(14) If ABCD is a cyclic quadrilateral and angle APC is x0, then angle ADC = 900 – x/2 and angle ABC = 900+x/2.
(15) If AB, BC, CD and AD are tangents on the given circle, then x0+y0 = 180 degree.
(16) If you find such diagram and angle ADB = x0 then angle ACB = 1800 -x0.
(17) If AB is the diameter of the bigger circle and ‘r’ is the radius of the smaller circle.
A B
(18) If AB is the tangent of two circles at A and B, P is the point at which both circles meet. Then, angle APB will be 900.
(19) If there are two circles of same radius ‘R’ and the distance between their centres is ‘R’.
Then, the length of common chord CD = √ 3 R.
20. How to find the distance between two chords?
(a) If chords are on the opposite sides of centre
Let ‘a’ and ‘b’ are the length of chords and ‘d’ is the distance between them.
If it follows this relation,
Then, we can say that
(b) If chords are on the same side of centre
Let ‘a’ and ‘b’ are the length of chords and ‘d’ is the distance between them.
If it follows this relation,
Then, we can say that
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