On turning a corner a car driver driving at 36 km per hour find the side on the road 55m ahead he immediately applies brakes so as to stop within 5 M of the child calculate the retardation produced and the time taken by the car to stop.

By Ritesh|Updated : November 13th, 2022

The retardation produced and the time taken by the car to stop is 1m/s² and 10 sec. Steps to calculate the retardation produced and the time taken by the car to stop:

Given that:

Initial velocity = u = 36km/h

Now by converting them we get:

u = 36x(5/18)=10m/s

Also given that:

Final velocity = V = 0 m/s

We have to calculate acceleration, a, and time t.

Distance traveled = S

S = 55 - 5 = 50m

We have the third equation of motion,

V² - U² = 2as

Substituting the values in the above equation we get

⇒0²-(10)² = 2*a*50

a= -100/100

In simplification we get the:

a= -1m/s².

We know that,

V = U + at

Substituting the values in the above equation we get:

0 = 10 - 1 x t

-10 = -1 x t

In simplification we get the:

t = 10sec

Hence, acceleration is -1m/s² or retardation =1m/s²

Therefore time is taken by the car to stop = 10sec.

Velocity

  • The pace at which an object's position changes in relation to time and a frame of reference is known as its velocity.
  • Velocity is nothing more than the act of moving quickly in one direction, despite its complex appearance.
  • Because velocity is a vector quantity, the definition requires both magnitude (speed) and direction.
  • The SI equivalent is the metre per second (ms-1).
  • It is said that a body is accelerating if its velocity changes in either direction or magnitude.

Summary:

On turning a corner a car driver driving at 36 km per hour find the side on the road 55m ahead he immediately applies brakes so as to stop within 5 M of the child and calculates the retardation produced and the time taken by the car to stop.

On turning a corner a car driver driving at 36 km per hour finds the side of the road 55m ahead he immediately applies brakes so as to stop within 5 M of the child. The retardation produced and the time taken by the car to stop is 1m/s² and 10 sec.

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