Number of atoms present in 120 amu of Ca are
By BYJU'S Exam Prep
Updated on: September 13th, 2023
Given that the mass of calcium is 120 amu
We have to find the number of atoms present in 120 amu of Ca.
We know that number of moles = number of atoms/Avogadro number = given mass/Molar mass
i.e., Number of moles = N₀ / Nₐ = W/M
Table of content
We know that 1 amu = 1.66056 x 10-24 g
So, 120 amu of Ca = 120 x 1.66056 x 10-24 g
Nₐ = 6.022 x 1023
Also, the molar mass of calcium = 40
Now, N₀ / 6.022 x 1023 = 120 x 1.66056 x 10-24 / 40
N₀ / 6.022 x 1023 = 3 x 1.66056 x 10-24
N₀ = 3 x 1.66056 x 10-24 x 6.022 x 1023
= 3 x 9.999 x 10-1
= 3 x 9.999/10
= 3 x 0.999
= 3 x 1
= 3
Therefore, the required number of atoms is 3.
Summary:
The number of atoms present in 120 amu of Ca is
The number of atoms present in 120 amu of Ca is 3.
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