If p and q are Zeroes of Polynomial f(x)=2x²-7x+3 Find the Value of p²+q²

If p and q are Zeroes of Polynomial f(x)=2x²-7x+3 Find the Value of p²+q²

Solution:

To find the value of p² + q², we need to substitute the zeros of the polynomial f(x) = 2x² - 7x + 3 into the expression.

Let's denote p and q as the zeros of f(x).

Therefore, we have p + q = 7/2 and pq = 3/2

Now, we can calculate p² + q²:

p² + q² = (p + q)² - 2pq

Substituting the values we know:

= (7/2)² - 2(3/2) = (49/4) - 6/2 = (49/4) - 3 = 49/4 - 12/4 = 37/4

Therefore, the value of p² + q² is 37/4.

Answer:

If p and q are Zeroes of Polynomial f(x)=2x²-7x+3, Then the Value of p²+q² is 37/4

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