f(t) = t2 − 4t + 3, Find the Value of α4β3 + α3β4.
The question states "If α and β are the zeros of the quadratic polynomial f(t) = t2 − 4t + 3, find the value of α4β3 + α3β4.” At most, a polynomial function can have real roots equal to its degree. Set a function's value to zero and solve to find its roots.
The polynomial zeros are the locations where the overall value of the polynomial equals zero The degree of a polynomial is the largest power of the variable x. The steps to find the value of α4β3 + α3β4 are as follows:
Since α and β are the zeros of the quadratic polynomial f(t) = t2 − 4t + 3.
Product of zeros = αβ = constant term/coefficient of x2 = 3
Sum of zeros = α + β = -coefficient of x/coefficient of x2 = 4
Given, α4β3 + α3β4
α3β3(α+β)
(3)3*(4) = 27 * 4 = 108
Hence, if α and β are the zeros of the quadratic polynomial f(t) = t2 − 4t + 3, the value of α4β3 + α3β4 is 108.
Summary:
If α and β are the zeros of the quadratic polynomial f(t) = t2 − 4t + 3, find the value of α4β3 + α3β4.
The value of α4β3 + α3β4 is 108, if α and β are the zeros of the quadratic polynomial f(t) = t2 − 4t + 3. Polynomial is made up of two terms, where Poly (means “many”) and Nominal (means “terms.”). The polynomial 2x2 + 5x + k indicates the addition operation. The degree of a polynomial is the highest power of the variable x. Substitute the value of the product of zeros and the sum of zeros in α3β3(α+β) and get the desired result.
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