What is the hybridisation state of xenon in XeOF4?

By Sukrati Saxena|Updated : July 11th, 2022

Hybridization of xeof4 is sp3 d2 and 1. In XeOF4, the π bond is equal to 1 and the σ bond is equal to 5. The Lone pair is equal to 1. Thus, by Adding a sigma bond and lone pair the expected answer is 5 + 1 which is equal to 6. This means that Xe will need its s-orbital, three p-orbitals, and two d-orbitals. This makes it clear that the hybridization will be SP3D2

Answer: Hybridization of xeof4 is sp3 d2 and 1

The hybridization and Valence shell electron pair repulsion theory helps in determining the geometry and shape of the molecule.Hybridization is the intermixing of a particular number of atomic orbitals so as to form an equal number of new orbitals. This has the same shape and energy.

Summary

What is the hybridisation state of xenon in XeOF 4?

Hybridization of xeof4 is sp3 d2 and 1. In XeOF4, the π bond is equal to 1 and the σ bond is equal to 5. The Lone pair is equal to 1. Thus, by Adding a sigma bond and lone pair the expected answer is 5 + 1 which is equal to 6.

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