How many liters of oxygen at STP is required to burn 60 grams of C2H6?

By Ritesh|Updated : November 11th, 2022

156.8 L of oxygen at STP is required to burn 60 grams of C2H6. Steps to find how many liters of oxygen at STP is required to burn 60 grams of C2H6:

C2H6 + (7/2)O2 → 2CO2 + 3H2O

At 0 60g

2 mole7 moles

Volume of O2 required = nO2 x 22.4

= 7 x 22.4

= 156.8 L

Ethane

A saturated hydrocarbon that exists in a gaseous state is ethane. Methane is the simplest alkane, with ethane coming in second. It has 6 hydrogen atoms and 2 carbon atoms. Ethane's chemical formula is C2H6. It is made using a laboratory procedure using sodium propionate. The most significant gaseous fuel is ethane. Ethane and other heavier hydrocarbons found in natural gas can be readily removed from the gas stream and liquefied at moderate pressure.

Uses of Ethane:

  • A small portion of what is produced in the natural gas liquids plants alone is used in the petrochemical industry.
  • used in the production of acetaldehyde, ethanol, and acetic acid, which are used to make paints, varnishes, adhesives, plastics, and other products.
  • used as the most accurate volatile marker for lipid peroxidation research.
  • used to create ethylene, which is used to ripen food to make polymers and antifreeze.

Physical Properties:

  • Odour-Odourless
  • Appearance-colorless gas
  • Covalently-Bonded Unit-7
  • Heavy Atom Count-2
  • Nature of compound-Saturated compound
  • Solubility-Soluble in water

Summary:

How many liters of oxygen at STP is required to burn 60 grams of C2H6?

156.8 L of oxygen at STP is required to burn 60 grams of C2H6. Special oxygen chambers are used in case of high pressure to increase the partial pressure of oxygen around the patient.

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