How do you Balance the Equation Al(s) + HCl(l) → AlCl3 (s) + H2(g)?

Step 3: Divide the reactions of reduction and oxidation.

Write the couplets for reduction and oxidation.

Reduction: Since hydrogen's oxidation state moves from +1 in hydrochloric acid to 0 in hydrogen gas, the reaction is a half-reaction in reduction.

HCl → H₂

A half-reaction of oxidation occurs when the oxidation state of aluminium moves from 0 in the metal state to +3 in the trichloride form of aluminium.

Al → AlCl₃

Step 4: Balancing all atoms except Hydrogen and Oxygen.

All elements, save Hydrogen and Oxygen, should be in balance. Multiplying HCl by 3 will balance the chlorine atoms on either side.

The reaction is,

Al(s) + 3HCl(l) → AlCl₃ (s) + H₂(g)

Aluminium Hydrochloric acid Aluminium chloride Hydrogen

Step 5: Balancing of Oxygen and Hydrogen.

Balance the Hydrogen atoms.

To balance the Hydrogen atom multiply Al and AlCl₃ by 2, H2 by 3, and HCl by 2

Hence, Al(s) + 3HCl(l) → AlCl₃ (s) + H₂(g) is the balanced reaction

Summary:-

How do you Balance the Equation Al(s) + HCl(l) → AlCl3 (s) + H2(g)?

The balanced chemical reaction of Al(s) + HCl(l) → AlCl₃ (s) + H₂(g) is Al(s) + 3HCl(l) → AlCl₃ (s) + H₂(g)

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