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GATE 2023 Analog Circuits Quiz 53
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Question 1
The purpose of emitter bypass capacitor in a CE BJT amplifier is to
Question 2
Calculate the input resistance Ri (in ohms) of the common base amplifier shown.
(consider C1, C2 to very large)
(choose RE = 1kΩ, R1 = 18kΩ,
R2 = 18kΩ, β = 99, rπ =1kΩ, RC = 5kΩ, VCC = 15V)
Question 3
The common emitter circuit, with bypass capacitor removed, is shown in Fig. The hfe = 75, hoe = 1μs, hre = 0, hie= 2.1kΩ
Find the input impedance, Zin (in kΩ).
Question 4
For the amplifier shown in the figure below, the BJT parameter are VBE = 0.7 V, β = 200, and thermal voltage, VT = 25 mV. The voltage gain of the amplifier is
Question 5
In below figure, both transistors are identical and have a high value of 'β', VBE =0.7V and VT = 25 mV. The small signal low frequency voltage gain AV = (V0/Vi) is equal to
Question 6
For the following given circuit, find the small signal voltage gain for β = 80 & VA = ∞ and VT = 26 mV.
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Oct 26ESE & GATE EC