Formulas and Shortcuts to solve Percentage For SSC & Other Competitive Exams 2022

By PARUL RISHI|Updated : July 21st, 2022

Today, we will cover a crucial topic from the quantitative aptitude section. Percentage. These formulas and shortcuts will be helpful for your upcoming SSC and Railway Exams 2022. If you like it let us know by giving it an upvote.

If you want to score good marks in the percentage part of the maths section, Read the complete article, to get the complete information. 

Percentage

The percentage is per‑cent which means parts per hundred.

Percent sign

The percent sign is the symbol: %

It is written to the right side of the number: 50%

Percentage Definition

Percentage is a value that represents the proportion of one number to another number.

1 percent represents 1/100 fraction.

If we have to convert percentage into a fraction than it is divide by 100.

Example 1: if we write 45% then its equal to 45/100 or in fraction 9/20 or in decimal 0.45

If we have to convert a fraction into a percentage, we have to multiple with 100.

Example 2: if we write 3/5 in fraction it is equal to 60% =3/5×100=60.

Convert Percentage into Decimal:

20% = 20/100 = 0.5

Convert Decimal into Percentage:

0.25 = (0.25 × 100) % = 25%

1.50 = (1.50 × 100) % = 150%

Here is a table of commonly used values shown in Percent, Decimal and Fraction:

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Types of Formulas and Short Tricks

Type 1: Percentage Increase/Decrease:

If the price of a commodity increases by R%, then the reduction in consumption so as not to increase

the expenditure is: [R/ (100 + R)] x 100%

If the price of a commodity decreases by R%, then the increase in consumption so as not to decrease

the expenditure is: [R/ (100 – R)] x 100%

Type 2: Results on Population:

Let the population of a town be P now and suppose it increases at the rate of R% per annum, then:

  1. Population after n years = P (1 + R/100) n
  2. Population n years ago =P/ (1 + R/100) n

Type 3: Results on Depreciation:

Let the present value of a machine be P. Suppose it depreciates at the rate of R% per annum. Then:

  1. Value of the machine after n years = P (1 – R/100) n
  2. Value of the machine n years ago = P/ [(1 – R/100)] n
  3. If A is R% more than B, then B is less than A by = [R/ (100 + R)] x 100%
  4. If A is R% less than B, then B is more than A by = [R/ (100 – R)] x 100%

Note: For two successive changes of x% and y%, net change = {x + y +xy/100} %

Attempt Percentage Quiz for SSC and Railway Exam

To enhance your practice, you can attempt these free quizzes, the link for which is provided below:

Name of Quizzes

Direct Link of Quiz

Percentage Quiz 1

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Percentage Quiz 2

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Percentage Quiz 3

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Percentage Quiz 4

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Percentage Quiz 5

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