√3x² - 8x + 4√3 = 0 can be factorized as:
√3x² - 6x - 2x + 4√3 = 0
(√3x - 2)(x - 2√3) = 0
Therefore, the solutions to the quadratic equation are:
√3x - 2 = 0 or x - 2√3 = 0
√3x = 2 or x = 2√3
Dividing both sides of the equation √3x = 2 by √3, we get:
x = 2/√3 = (2√3) / 3
Therefore, solutions to the quadratic equation √3x² - 8x + 4√3 = 0 are x = (2√3) / 3 and x = 2√3.
- Find the Zeros of the Quadratic Polynomial 4u²+8u and Verify the Relationship between the Zeros and the Coefficient.
- Write the Zeros of the Quadratic Polynomial f(x) = 4√3x² + 5x - 2√3
- For the Following, Find a Quadratic Polynomial whose Sum and Product Respectively of the Zeros are as Given. Also Find the Zeroes of the Polynomial by Factorization: 21/8, 5/16
Commentswrite a comment