Find the smallest 4 digit number divisible of 18, 24 and 32.

By Ritesh|Updated : November 3rd, 2022

The smallest 4 digit number divisible of 18, 24 and 32 is 1152. Calculate the necessary value. The factors are 18, 24, and 32

  • 18 = 2 x 3 x 3
  • 24 = 2 x 2 x 2 x 3
  • 32 = 2 x 2 x 2 x 2 x 2

Thus, the LCM of 18, 24, and 32 is 2 x 2 x 2 x 2 x 2 x 3 x 3 = 288.

Write the multiples of 288 in order to determine the smallest four-digit number that may be divided by 288.

  • 288 x 2 = 576
  • 288 x 3 = 864
  • 288 x 4 = 1152

Properties of Factors

  • Every natural number is a factor of itself
  • 1 is a factor of each number
  • All the whole numbers have at least two factors apart from 0 and 1
  • The number of factors of a given number is finite
  • Every factor is less than or equal to the given number
  • Factors can be evaluated using both multiplication and division methods
  • 1152 is the smallest 4-digit number that can be divided into 18, 24, and 32.

Summary:

Find the smallest 4 digit number divisible of 18, 24, and 32.

1152 is the smallest four-digit number that is divisible by 18, 24, and 32. Factors are the numbers that can divide a number exactly. It means that after division no remainder is left behind.

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