# Find the Largest Number Which Divides 615 and 963 Leaves the Remainder 6 in Each

By K Balaji|Updated : November 7th, 2022

87 is the largest number which divides 615 and 963 leaves the remainder 6 in each.

To Find the HCF for the given set of numbers.

Let x be the required largest number

Subtract 6 from 615 and 963

615 - 6 = 609

963 - 6 = 957

Now we have to Find HCF using prime factorization method,

609 = 29 x 3 x 7

957 = 29 x 11 x 3

The common factors are 29 and 3

x = 29 x 3

x = 87

### HCF - Highest Common Factor

The abbreviation for this phrase is Highest Common Factor. The HCF of two numbers is the highest factor that may divide two integers equally. It is possible to evaluate HCF using two or more numbers. It is the most effective divisor for any pair of integers that may evenly or completely divide the inputted numbers.

How to find HCF?

Any given collection of numbers can have its HCF calculated in one of two ways:

1. by prime factorization method
2. by division method

HCF by prime factorization method

The methods below will show you how to calculate a number's HCF using the prime factorization method.

Step 1: Summarize each integer's prime factors for each integer. This approach is known as prime factorization.

Step 2: List the components that both numbers share in step two.

The HCF is the total of all the common prime factors in step three ( use the lower power of each common factor)

HCF by division method

Step 1: Write the numbers given horizontally in the correct order, separating them with commas.

Step 2: Determine which prime number is the smallest that may divide the specified number in Step 3. It must accurately divide the given numbers. (Complete the left side.)

Write the quotients now in step three.

Step 4: Repeat steps 1 through 3 until no more coprime numbers remain.

Step 5: We will find the common prime factors because the factors on the left side evenly divide each integer. These typical prime factors add up to the HCF of the given numbers.

Summary:-

## Find the Largest Number Which Divides 615 and 963 Leaves the Remainder 6 in Each

87 is the largest number which divides 615 and 963 leaves the remainder 6 in each. HCF of two numbers is the highest factor which divides the two numbers, evenly. It can be found for two or more than two numbers.

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