Find the largest number that will divide 398 , 436 and 542 leaving remainders 7 , 11 and 15 respectively

By K Balaji|Updated : November 12th, 2022

The largest number that will divide 398, 436, and 542 leaving remainders 7, 11, and 15 respectively is 17.

The greatest number that will divide 398, 436, and 542 and leave the corresponding remainders of 7, 11, and 15 must be found. Consequently, we must determine the HCF of three numbers: 398-7, 436-11, and (542-15).

Hence,

436 - 11 = 425

398 - 7 = 391

542 - 15 = 527

Now, we have to find the hcf (391, 425, 527) = 17

Therefore, 17 is the highest integer that will divide 398,436 and 542, leaving 7, 11, and 15 as the remainders.

Numbers

A number is an arithmetic value that is used to calculate and represent a quantity. Numerical symbols, such as "3," are written to represent numbers. A number system is a logical way of writing numbers that uses digits or symbols to represent them. the system of numbers

  • represents a practical collection of numbers.
  • reflects a number's arithmetic and algebraic structure.
  • Standard representation is offered.

Number Series

In mathematics, a number series is a set of numbers where each term is a different number, and the following term is formed by either adding or subtracting the previous term from the previous term. Consider the series 1, 3, 5, 7, and 9, for instance. The constant term "2" is added to the preceding term in this series to produce the subsequent term. Numerous varieties of number series exist, including:

  • Perfect Square series
  • Two-stage type series
  • The odd man out series
  • Perfect cube series
  • Geometric series
  • Mixed series

Summary:-

Find the largest number that will divide 398, 436, and 542 leaving remainders 7, 11, and 15 respectively

The biggest number that will divide 398, 436, and 542 with 7, 11, and 15 as the remaining fractions is 17.

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