We know that
d/dx ln x = 1/x
So we will use the counter process to determine the integral of 1/x
Integral of 1/x is loge |x|, which is the natural logarithm of absolute x represented as ln x
The integral identity of xn cannot be used here as
xn dx = xn + 1/(n + 1) + C
For 1/x here, we have n = -1
x-1 dx = x0/0 = undefined.
If it is an indefinite integral, we add a constant C
We can find the specific value by specifying the limits
Therefore, the integral of 1/x is logx + C.
Find the integral of 1/x.
The integral of 1/x is logx + C.