Find the integral of 1/x?

We know that

d/dx ln x = 1/x

So we will use the counter process to determine the integral of 1/x

Integral of 1/x is loge |x|, which is the natural logarithm of absolute x represented as ln x

The integral identity of xn cannot be used here as

xn dx = xn + 1/(n + 1) + C

For 1/x here, we have n = -1

x-1 dx = x0/0 = undefined.

If it is an indefinite integral, we add a constant C

We can find the specific value by specifying the limits

Therefore, the integral of 1/x is logx + C.

Summary:

Find the integral of 1/x.

The integral of 1/x is logx + C.

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