Estimate the Mass of Urea (NH2CONH2) required in making 2.5 kg of 0.25 Molal Aqueous Solution

By BYJU'S Exam Prep

Updated on: September 25th, 2023

The mass of urea (NH₂CONH₂) required in making 2.5 kg of 0.25 molal aqueous solution is 36.95 kg

Given that Mass of solution given is 2.5 kg and

Also given that Number of moles of urea 0.25 m

The molar mass of urea (NH₂CONH₂)

NH₂CONH₂ = 14 + 2 x 1 + 12 + 16 + 14 + 2 x 1 = 60 g mol^-1

Consequently, the urea mass will be

Number of moles of urea x Molar mass of urea

Additionally, 0.25 moles of urea will weigh

0.25 mol x 60 g mol^-1

= 15g

Thus, the mass of the solution is 1000 g + 15 g = 1015 g

1015 g of aqueous solution contains urea = 15g

2500 g of aqueous will requires urea = 15/ (1015kg x 2500 g) = 36.95 g

Therefore, 36.95 kg of urea must be used to produce 2.5 kg of 0.25 molal aqueous solution.

Table of content

It serves as a fertiliser with nitrogen release.
It serves as a stabiliser in explosives made of nitrocellulose.
It is a crucial reagent in lanthanide chemistry.
It is employed in the production of powerful explosives, such as urea nitrate.
It is a component of dish soap and hair removal creams. It is used in creams or ointments to rehydrate skin. It is used in the urea breath test to identify the presence of bacteria in the stomach.
It serves as a browning agent for manufacturing pretzels.
It is employed in the production of melamine.

Summary:-

Estimate the Mass of Urea (NH₂CONH₂) required in making 2.5 kg of 0.25 Molal Aqueous Solution

To make 2.5 kg of 0.25 molal aqueous solution, 36.95 kg of urea (NH₂CONH₂) is needed.

Related Questions:-