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Equal volume of N2 and H2 react to form ammonia under suitable condition then the limiting reagent.

By BYJU'S Exam Prep

Updated on: September 25th, 2023

Equal volumes of N2 and H2 react to form ammonia under suitable conditions then the limiting reagent is H2. Steps to solve the limiting reagent:

Let the volume of N2 and H2 = 3L

Hence the balanced chemical equation is N2 + H2 → 2NH3

According to the above-mentioned balanced equation:

  • 1V of N2 requires 3V of H2
  • 1V of N2 reacts with 3V of H2 to produce 2V of NH3
  • 3V of N2 will require 9V of H2

But we have only 3V of H2

Hence H2 is LR

Now,

3V of H2 will react with 1V of N2

Unreacted N2 = 3 – 1 = 2V

Uses of ammonia

  • In the home, NH3 is mixed with water to clean stainless steel and glass. It is utilised as fertiliser since it boosts crop output.
  • It serves as an antibacterial agent in food products.
  • It is used to neutralise pollutants like nitrogen oxides generated from diesel engines, as a refrigerant, as a pH adjuster in the fermentation process, and in the fermentation industry.
  • It serves as fuel for rocket motors.

Summary:

Equal volume of N2 and H2 react to form ammonia under suitable condition then the limiting reagent.

H2 is the limiting agent in an equal volume of N2 and H2 react to form ammonia under suitable condition. Ammonia is utilised in the textile industry to create synthetic fibers like rayon and nylon.

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