Combined Correction for a Distance of 2500 m is

By Aina Parasher|Updated : July 6th, 2022

Combined correction for a distance of 2500 m is-

  1. 0.49 m
  2. 0.07 m
  3. 0.42 m
  4. 0.56 m

Answer: C. 0.42 m

Combined correction for a distance of 2500 m is 0.42 m.

Solution

Correction due to curvature,

CC=d2/2R

where,

d = horizontal distance between 2 points (in km)

R = radius of curvature of earth = 6370 kms

CC=0.0785d2

d is substituted in kms and CC value will be in m

Correction due to curvature is always negative

Correction due to refraction,

CR=17 CC 

CR =0.0112d2

d = horizontal distance between 2 points (in km)

CR = corrections due to refraction (in m)

Correction due to refraction is always positive

Combined correction,

C = CR  - CC

C= 1/7CC - CC 

C= -6/7 CC 

C= -0.0673d2

d is substituted in kms and C value will be in m

Combined correction for a distance of 2500 m is

C=0.0673×2.52 (negative)

(d = 2500 m = 2.5 km)

C = 0.42 m

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