# Time, Speed & Distance Questions, Study Notes for CLAT 2022 - 2023 & Other Law Entrance Exams

By Aman Prakash|Updated : February 14th, 2022

Time, Speed & Distance is a topic that is always asked in the CLAT exam. As per previous year CLAT questions on time speed and distance, questions are often asked in the quantitative techniques section. Our subject experts have explained all the basic concepts and short strategies of an important topic namely Speed, Distance and Time.

To help you score well, we are here to give you basic ideas and tips on how to solve Speed, Distance & Time questions along with time speed and distance CLAT questions. It is also important to understand the types of questions asked on this topic. You can also solve CLAT question papers to practice past year CLAT questions on Time, Speed & Distance

## CLAT Exam: What is Speed, Distance, and Time?

Understand the concept of Speed, Distance, and Time to be able to solve the questions with ease.

### Speed:

Speed ​​is easily defined as the distance covered by each unit of time. Statistically, it is defined as:

• Speed ​​= Distance travelled / Duration

• Time Formula by distance and speed: Time = Range / Speed

• Range formula in terms of Speed ​​and Time: Range = (Speed ​​Time -X)

• It is very important to know the value of the unit while solving these types of problems.

• SI Unit Speed: Meter per second

• SI Unit Range: Meter

• SI Unit Time: Second

All formulas in speed, time, and distance are related. One needs to connect the information provided to the problems intelligently and this can be easily done with good practice. Now let's talk about the different types of Speed, Distance & Time questions.

## Types of Time Speed and Distance Questions in CLAT Exam

Speed ​​Time & Distance is one of the most frequently asked quantitative aptitude topics in entrance exams. This is one of the topics that candidates are familiar with before they start preparing for a competitive exam.
The concepts of speed, time, and distance are the same, but the types of questions asked in the exam may differ.
Most of the 12-word questions asked are based on speed, time, and distance, but candidates are also prepared to ask about data adequacy and data interpretation based on the TDS (time, distance, speed) topic. need to do it.
Introducing speed, distance and time concepts, formulas and rules to get ready and ace the tough competition. Further on in the article, in addition to speed, distance, and time tricks, there are some sample questions. Go through the time speed and distance of all types of questions in the CLAT exam below.

## Speed, Time, Distance Relationship (Formulas) for CLAT

• Speed ​​= Distance / Time-This shows how slow or fast the object is moving. It is the covered distance divided by the time it takes to cover that distance.

• Speed ​​is directly proportional to distance and inversely proportional to time. Therefore,

• Distance = speed x time and

• Time = distance / speed. The higher the speed, the shorter the time required and vice versa.

You can use these formulas to solve all the basic problems. However, when using formulas, it is also important to use the units correctly.

### Type 1 - Basic Questions for CLAT

Now, we will discuss the most frequently used concept in this chapter i.e. questions based on the unit conversion. So, in order to learn this concept, we need to know how these questions are framed in the question paper.

Question: A train runs at X km/hr and it takes 18 seconds to pass a pole. The length of the train is 180m. Find the speed of the train in km/hr.

Solution:

Speed = distance /Time

Therefore,

S=180m/18s= 10m/s

Now we need the answer in km/hr and for that, we will multiply the given speed with (18/5) in order to get the answer in km/h

Therefore, S= 10*(18/5)=36km/h.

So here the trick for the same is :

• Convert metre per second (m/sec) to km per hr (km/h)
For converting (meter per second) to (kilometer per hour) we use the following formula

s m/sec= S *(18/5)  km/h

• Convert km per hr (km/h) to metre per second (m/sec)
For converting kph(kilometer per hour) to MPs(meter per second) we use the following formula

S km/hr=(s∗5/18) m/sec

Question: A boy covers a distance of 600m in 2min 30sec. What will be the speed in km/hr?

#### Solution:

Speed =Distance / Time =Distance covered = 600m, Time taken = 2min 30sec = 150sec
Therefore, Speed= 600 / 150 = 4 m/sec = 4m/sec = (4*18/5) km/hr = 14.4 km/ hr

### Type 2 - Relative Speed Questions for CLAT

Considering 2 objects A and B having the speed x, y.

• If the ratio of the speeds of A and B is x:y, then the ratio of the times taken by them to cover the same distance is: 1/x: 1/y  or  y: x

Question: The ratio of the speed of a bike and a motor is 4:5 then what will be the ratio for the time taken by both the vehicles for the same destination?

Solution:

As the destination is the same so distance will be the same for both Car and bike.

Let the Distance be d

And the speeds for both the vehicles be 4s and 5s

Now, t1 = d/4s----(1)

t2 = d/5s----(2)

so,t1/t2 = 5/4= 5:4

### Type 3 - Average Speed Questions for CLAT

• Average Speed is another very important concept. It is defined as:

Average Speed = Total Distance Travelled /Total Time Taken

Question: Dewansh travels 320 km at 64 km/hr and returns at 80 km/hr. Calculate the average speed of Dewansh?

Solution:

We know that speed = Distance/ time taken
⇒ ∴Total time taken = 320/64 + 320/80 = 9
⇒ Average Speed = (320 + 320)/9
⇒ Average speed = 71.11 km/hr

Question: A car moving with a uniform speed of 50km/h covers half the distance with this speed. Half of the time of the remaining distance is covered with a speed of 35km/h and the other half time at 10km/h. If the total distance travelled is 90 km then What was the car’s average speed (approximately) during his entire journey?

Solution:
Half of total distance = 45km, Speed = 50km/h
Time taken = 45km/50 = 0.9 hr = 0.9 x 60 = 54 minutes

Let time taken for remaining 45 km be T
And, distance via speed 10km/hr by D

Then, ATQ, T/2 = (45 - D) / 35 …(1)

And, T/2 = (D) / 10 …(2)

Equating equations 1 & 2,
(45 - D) / 35 = (D) / 10
10(45 - D) = 35D
45D = 450 or,
D = 10 km, T= 2 hour
Total time = 2+.9= 2.9 hour

Average speed= 90/2.9=31km/hr

### Type 4

• Suppose a Person covers a certain distance at x km/hr and an equal distance at y km/hr.

Then, the average speed for the complete Journey: 2xy/(x + y)

Question: A train goes from Ballygunge to Sealdah at an average speed of 20 km/hour and comes back at an average speed of 30 km/hour. The average speed of the train for the whole journey is?

#### Solution:

Let x and y be the average speed for the same distance in two different times.
Then, average speed = (2xy)/(x + y)
A train goes from Ballygunge to Sealdah at an average speed of 20 km/hour and comes back at an average speed of 30 km/hour.
The average speed of train = (2 × 20 × 30)/(20 + 30) = 24 km/hr

Question: A boy goes to school at a speed of 3 km per hr and returns to the village at a speed of 2 km per hr. If he takes 5 hrs in all, what is the distance between the village and the school?

Solution:

Let the required distance be x km.
Then time taken during the first journey = x/3 hr.
and time taken during the second journey = x/2 hr.
x/3 + x/2 = 5 => (2x + 3x) / 6 = 5
=> 5x = 30.
=> x = 6
Required distance = 6 km.

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## FAQs

• The formula for time is given as [Time = Distance ÷ Speed]. To calculate the speed, the time formula will be applied as [Speed = Distance Travelled ÷ Time].

• The basic formula speed is given as  Speed= Distance/Time . From this formula, it is quite evident that speed is directly proportional to distance and inversely proportional to time.

• To calculate speed, divide the distance of the journey by the time it took to travel, so speed = distance divided by time. To calculate time, divide distance by speed. To get the distance, multiply speed by time.

To know more, you are advised to go through all the formulas related to Time, Speed and Distance.

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