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Class XI Physics Laws of Motion Quiz 1

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Question 1

Find the acceleration of 3 kg mass when acceleration of 2 kg mass in 2ms–2 as shown in figure.

Question 2

Block of 3 kg is initially in equilibrium and is hanging by two identical springs A and B as shown in figures. If spring A is cut from lower point at t = 0 then, find acceleration of block in ms–2 at t = 0.

Question 3

Two masses of 10 kg and 20 kg respectively are connected by a massless spring as shown in figure. A force of 200 N acts on the 20 kg mass at the instant when the 10 kg mass has an acceleration of 12 ms–2 towards right, the acceleration of the 20 kg mass is

Question 4

Two blocks are connected by a spring. The combination is suspended, at rest, from a string attached to the ceiling, as shown in the figure. The string breaks suddenly. Immediately after the string breaks, what is the initial downward acceleration of the upper block of mass 2m?

Question 5

Find the direction of friction forces on block C and D . (Assume all surfaces are rough and all velocities are with respect to ground).

Question 6

In the arrangement shown in the figure, mass of the block B and A is 2 m and m respectively. Surface between B and floor is smooth. The block B is connected to the block C by means of a string pulley system. If the whole system is released, then find the minimum value of mass of block C so that block A remains stationary with respect to B . Co-efficient of friction between A and B is μ.

Question 7

With what minimum velocity should block be projected from left end A towards end B such that it reaches the other end B of conveyer belt moving with constant velocity v. Friction coefficient between block and belt is μ.

Question 8

Two masses A and B of 10 kg and 5 kg respectively are connected with a string passing over a frictionless pulley fixed at the corner of a table as shown in figure. The coefficient of friction of A with the table is 0.2 . The minimum mass (in kg) of C that may be placed on A to prevent if from moving is equal to:

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Avinash KumarAvinash KumarMember since Feb 2017
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