Calculate the volume occupied by 28u nitrogen gas

Number of moles of nitrogen gas of 28u having 1 molecule of nitrogen gas = 28/ (6.022 x 10²³ x 28)

= 1/6.022 x 10²³ [As 1 mole of nitrogen has 6.022 x 10^{2 3} molecules]

Volume occupied by 28u nitrogen gas = 1/(6.022 x 10²³ ) x 22.4 L

= 1/(6.022 x 10²³ ) x 22400 mL

= 3.719 x 10⁻² ⁰ mL of N2 gas

Therefore, the volume occupied by 28u nitrogen gas is 3.719 x 10⁻² ⁰ mL of N2 gas.

Summary:

Calculate the volume occupied by 28u nitrogen gas.

The volume occupied by 28u nitrogen gas is 3.719 x 10⁻² ⁰ mL of N2 gas.

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