2. Number of atoms on both sides after balancing
Number of atoms on the reactant side
Number of atoms on the product side
3. By balancing a number of atoms on both sides
- The number of atoms on both sides is not equal
- Let us balance the atom that is in a larger amount
- The element oxygen contains a large number on the reactant side as 12 and on the product side as 4. Convert 4 to 12 by substituting 3 as the coefficient before it
- By substituting 4 as the coefficient before Barium Sulfate, both barium and sulphur become 3, and sulphur is balanced as it is 3 on the reactant side
- Balance barium atoms as 3 on both sides by substituting 3 as the coefficient before barium chloride
- On the reactant side, chlorine becomes 6 in number so to balance it substitute 2 as the coefficient before aluminum chloride
- Both chlorine and aluminum are now balanced.
By balancing the equation
Al2(SO4)3 + 3BaCl2 --> 2AlCl3 + 3BaSo4
Therefore, the reaction barium chloride reacts with aluminium sulfate to give aluminium chloride and a precipitate of barium sulfate is translated and balanced.
Barium chloride reacts with aluminium sulfate to give aluminium chloride and a precipitate of barium sulfate. Translate and balance
The reaction barium chloride reacts with aluminium sulfate to give aluminium chloride and a precipitate of barium sulfate is translated and balanced.
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