Barium chloride reacts with aluminium sulfate to give aluminium chloride and a precipitate of barium sulfate. Translate and balance

2. Number of atoms on both sides after balancing

Atom	Number of atoms on the reactant side	Number of atoms on the product side
Al	2	2
S	3	3
O	12	12
Ba	3	3
Cl	6	6

3. By balancing a number of atoms on both sides

• The number of atoms on both sides is not equal
• Let us balance the atom that is in a larger amount
• The element oxygen contains a large number on the reactant side as 12 and on the product side as 4. Convert 4 to 12 by substituting 3 as the coefficient before it
• By substituting 4 as the coefficient before Barium Sulfate, both barium and sulphur become 3, and sulphur is balanced as it is 3 on the reactant side
• Balance barium atoms as 3 on both sides by substituting 3 as the coefficient before barium chloride
• On the reactant side, chlorine becomes 6 in number so to balance it substitute 2 as the coefficient before aluminum chloride
• Both chlorine and aluminum are now balanced.

By balancing the equation

Al₂(SO₄)₃ + 3BaCl₂ –> 2AlCl₃ + 3BaSo₄

Therefore, the reaction barium chloride reacts with aluminium sulfate to give aluminium chloride and a precipitate of barium sulfate is translated and balanced.

Summary:

Barium chloride reacts with aluminium sulfate to give aluminium chloride and a precipitate of barium sulfate. Translate and balance

The reaction barium chloride reacts with aluminium sulfate to give aluminium chloride and a precipitate of barium sulfate is translated and balanced.

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