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An electric dipole is placed at an angle of 30° with an electric field intensity of 2 × 105 N/C. It experiences a torque equal of 4 Nm. The charge on the dipole, if the dipole length is 2 cm, is?
By BYJU'S Exam Prep
Updated on: September 25th, 2023
(a) 5 mC
(b) 7μC
(c) 8 mC
(d) 2 mC
The charge on the dipole, if the dipole length is 2 cm, is 2 mC. Steps to Know the charge on the dipole, if the dipole length is 2 cm:
Step 1: It is given:
Angle θ = 30°
Torque (τ) = 4Nm
Electric field (E) = 2 × 105 N/C
Dipole length (l) = 2 cm = 2 x 10-2 m
Step 2: Now we have to Calculate the charge on the dipole:
An electric dipole in a consistent electric field feels a torque () determined by
τ = pEsinθ
Where,
p = dipole moment
= q x l
Torque is:
τ = qlE sinθ
q = τ/lE sinθ
Substituting the values,
q = 4Nm/ (2 x 10-2 m x 2 × 105 N/C x sin 30°)
On simplifying we get
q = 4/ (4 x 103 x ½)
q = 2 x 10-3 C
q = 2 mC
A pair of opposing charges, q and -q, separated by a distance, d, is referred to as an electric dipole. Electric dipoles in space always point in the direction of positive charge q from negative charge -q. The dipole’s center is defined as the intersection of q and -q. A pair of electric charges with two opposite signs and equal magnitudes spaced apart is the simplest type of electric dipole.
Summary:
An electric dipole is placed at an angle of 30° with an electric field intensity of 2 × 105 N/C. It experiences a torque equal of 4 Nm. The charge on the dipole, if the dipole length is 2 cm, is?
An electric dipole is placed at an angle of 30° with an electric field intensity of 2 × 105 N/C. It experiences a torque equal of 4 Nm. The charge on the dipole, if the dipole length is 2 cm, is 2 mC.