An automobile vehicle has a mass of 1500 kg. What must be the force between the vehicle and the road if the vehicle is to be stopped with a negative acceleration of 1.7 m/s2?

By Ritesh|Updated : November 11th, 2022

The force between the vehicle and the road if the vehicle is to be stopped with a negative acceleration of 1.7 m/s2 is -2550 N. An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe forces. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

Steps to calculate the vehicle is to be stopped with a negative acceleration of 1.7 m/s2

Step 1: Given that:

The mass of the automobile in question is 1500 kg, and it is assumed that it is decelerating at an acceleration of 1.7 m/s2

So m = 1500 kg and a = -1.7 m/s2

Step 2: Formula used:

We are aware that mass times acceleration, or in other words, is the formula for force.

F = ma

Step 3: Find the required force:

As a result, the force F between the car and the road can be calculated as follows:

F = 1500 x (-1.7)

F = -2550

The absence of a positive sign indicates that the force is acting against the flow of motion.

Consequently, the vehicle's force on the road is -2550 N.

Summary:

An automobile vehicle has a mass of 1500 kg. What must be the force between the vehicle and the road if the vehicle is to be stopped with a negative acceleration of 1.7 m/s2?

An automobile vehicle has a mass of 1500 kg. The force between the vehicle and the road if the vehicle is to be stopped with a negative acceleration of 1.7 m/s2 is -2550 N. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.

Comments

write a comment

CDS & Defence Exams

CDSCAPFAFCATTA ExamACC ExamOther ExamsPracticePreparation

Follow us for latest updates