A train starting from a railway station and moving with uniform acceleration attains a speed of 40km/h in 10 minutes. Find its acceleration in the units of m/s².
By BYJU'S Exam Prep
Updated on: September 25th, 2023
A train starting from a railway station and moving with uniform acceleration attains a speed of 40km/h in 10 minutes. The acceleration in the units of m/s² is 0.0185. The rate at which an object’s velocity changes over time is known as acceleration. It has both a direction and a magnitude because it is a vector quantity. Calculations show that acceleration (a) is equal to the product of the velocity (v) and time (t) changes.
Table of content
Acceleration of Train
Acceleration can be calculated using the following formula:
Acceleration (a) = Change in velocity (Δv) / Change in time (Δt)
where, t denotes the change in time and v denotes the change in velocity. In the metric system, acceleration is commonly expressed in units of metres per second squared (m/s2).
It’s important to note that acceleration is not only related to changes in speed but also to changes in direction. For example, when an object moves in a circular path at a constant speed, it experiences acceleration because its direction is continuously changing.
Solution
Initial speed u = 0 m/s2
Final velocity v = 40 km/h = 40 x 5/18 = 100/9 m/s
Time t = 10 mins = 600 sec
Let us use the first equation of motion
v = u + at
Substituting the values we get
100/9 m/s = 0 + 600s x a
So we get
a = 100/(9 x 600) m/s2
a = 0.0185 m/s2
Therefore, its acceleration is 0.0185 m/s2.
Summary
A train starting from a railway station and moving with uniform acceleration attains a speed of 40km/h in 10 minutes. Find its acceleration in the units of m/s2.
A train starting from a railway station and moving with uniform acceleration attains a speed of 40km/h in 10 minutes. Its acceleration in the units of m/s2 is 0.0185.
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